Played around with CodeWars and some of the problems on there. Here's one of the solutions I came up with for a question to determine an outlier in the array (eg: one of the elements would be either odd or even).
function findOutlier(integers){
let odd = integers.filter(function(n) {return (n%2) !== 0;});
let even = integers.filter(function(n) {return (n%2) === 0;});
if (odd.length < even.length) {
return odd[0];
} else {
return even[0];
}
}